problem in creating analoge date

[hack_er4]

Hello friends,
I am creating a analog clock with analog day,date and month.
I am succeeded in analog day and month as they are linear.
but with date I can't able to write the script as every month end the keep on changing like jan 31
feb 28 and 29
mar 30
apr 31
.
.
.
.
.
dec 31

Is there any way to get those right every month?

Thanks,

[TweaknFreak]

Check out the code of this. Might be helpful.

http://limpet.deviantart.com/art/Rainmeter-Calendar-106839760

[thatsIch]

There are 2 possible ways:

- do everything hard coded like

Code: Select all

m = { 31, 28, 31, 30, ... }
print(m[currentMonth])

or just take a starttime like

Code: Select all

startTime = os.time{year=2012, month=8, day=1, hour=0}
oneDay = 86400000 (i guess cause 24*60*60*1000)
nextDay = startTime + oneDay

and then format the date with os.date

I prefer the hardcode way, cause its easier to read and understand, though I dont like hard-coded stuff like that

[Mordasius]

but with date I can't able to write the script as every month end the keep on changing.... Is there any way to get those right every month?

If what you want is the number of days in the current month taking account of leap years then you could use something like the following (which is really just an elaboration of thatsIch's 'hardcode' method):

Code: Select all

[mMonth]
Measure=Time
Format=%#m
UpdateDivider=-1

[mYear]
Measure=Time
Format=%Y
UpdateDivider=-1

[mLuaScript]
Measure=Script
ScriptFile=DaysInMonth.lua

[MtDaysThisMonth]
Meter=String
MeasureName=mLuaScript
FontColor=ffffff
FontSize=12
AntiAlias=1
Text="There are %1 days in the current month"
UpdateDivider=-1

DaysInMonth.lua

Code: Select all

function Initialize()
  monthDays = {31,28,31,30,31,30,31,31,30,31,30,31} 
  msMonth = SKIN:GetMeasure('mMonth')
  msYear = SKIN:GetMeasure('mYear')
end -->Initialize

function Update()
    SKIN:Bang('!DisableMeasure mLuaScript') -- script only needs to run once a month
    if leapYear(msYear:GetValue()) then monthDays[2]=29 end  	 -- handles leap years
  return monthDays[msMonth:GetValue()]  -- script returns number of days in the month
end -->Update

function leapYear(y) 
  return ((y%4==0) and not (y%100==0 and not(y%400==0)))
end -->leapYear

[hack_er4]

Thanks for the help Mordasius and thatsIch

I want them to put on the rotator.
Like this

[MerlinTheRed]

That's a different case. If you want to do something like this, it has to skip some days if they are not present in the current month. That's even easier to do. You just program the rotator like each month has 31 days. Then if a month has less days, it will jump e.g. from 28 to 1 at the end of February. No need to adjust anything.

[Mordasius]

I want them to put on the rotator.
Like this

DSC02624.JPG

Please tell me you want to make an analog clock showing the proportion of total days in the current month passed rather than just show the date from 1-31.

[hack_er4]

That's a different case. If you want to do something like this, it has to skip some days if they are not present in the current month. That's even easier to do. You just program the rotator like each month has 31 days. Then if a month has less days, it will jump e.g. from 28 to 1 at the end of February. No need to adjust anything.

I'll try this.
can You please suggest some code regarding this It will help me alot. thanks

[hack_er4]

Please tell me you want to make an analog clock showing the proportion of total days in the current month passed rather than just show the date from 1-31.

Thanks for asking.,
I just want the "hand" to point on the current date every month.
As MerlinTheRed suggested all month set to 31. If less than 31 then skip to 1.