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Substitute
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Re: Substitute
%B or %m. Either one works. The issue with your code is specificity.Alloutofmercy wrote: ↑January 12th, 2022, 2:11 pm Strange. It still dosent work. I thought you were right cause for some reason I thought %B will return a numeric value of the month instead of the name of the month. That was the reason I changed it to %B in the first placeCode: Select all
Screenshot 2022-01-12 193827.png
Code: Select all
[measureDate] Measure=Time Format=%m Substitute="1":"#@#Jan1.png","2":"#@#Feb2.png","3":"#@#Mar3.png","4":"#@#Apr4.png","5":"#@#May5.png","6":"#@#June6.png","7":"#@#July7.png","8":"#@#Aug.png","9":"#@#Sep9.png","10":"#@#Oct10.png","11":"#@#Nov.png","12":"#@#Dec12.png"
If you go for %B,
Code: Select all
[measureDate]
Measure=Time
Format=%B
Substitute="January":"#@#Jan1.png","February":"#@#Feb2.png","March":"#@#Mar3.png","April":"#@#Apr4.png","May":"#@#May5.png","June":"#@#June6.png","July":"#@#July7.png","August":"#@#Aug.png","September":"#@#Sep9.png","October":"#@#Oct10.png","November":"#@#Nov.png","December":"#@#Dec12.png"
If you use %m,
Code: Select all
[measureDate]
Measure=Time
Format=%m
Substitute="01":"#@#Jan1.png","02":"#@#Feb2.png","03":"#@#Mar3.png","04":"#@#Apr4.png","05":"#@#May5.png","06":"#@#June6.png","07":"#@#July7.png","08":"#@#Aug.png","09":"#@#Sep9.png","10":"#@#Oct10.png","11":"#@#Nov.png","12":"#@#Dec12.png"
the DA GALLERY For some Reason, the square root of X2 does not involve X
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Re: Substitute
Whew! Got it
Thankyou
Thankyou
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BOOTY
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Re: Substitute
You are WELCOMEAlloutofmercy wrote: ↑January 13th, 2022, 10:24 am Whew! Got it
Thankyou Screenshot 2022-01-13 155443.png
the DA GALLERY For some Reason, the square root of X2 does not involve X
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- Rainmeter Sage
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Re: Substitute
Use Format=%#m.Alloutofmercy wrote: ↑January 13th, 2022, 8:36 am You are right. Here is the package. The images were edited by me
https://docs.rainmeter.net/manual/measures/time/#FormatCodes
See the notes at the end of that section.
Edit: David beat me half way
from the Realm of Death
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Re: Substitute
Yeah, just half.
the DA GALLERY For some Reason, the square root of X2 does not involve X